Notice
Recent Posts
Recent Comments
Link
일 | 월 | 화 | 수 | 목 | 금 | 토 |
---|---|---|---|---|---|---|
1 | 2 | 3 | 4 | 5 | ||
6 | 7 | 8 | 9 | 10 | 11 | 12 |
13 | 14 | 15 | 16 | 17 | 18 | 19 |
20 | 21 | 22 | 23 | 24 | 25 | 26 |
27 | 28 | 29 | 30 |
Tags
- 이론
- MongoDB
- 실습
- network
- 쿠버네티스
- 용어정리
- node.js
- Docker-compose
- Docker Swarm
- 명령어
- git
- 도커
- 네트워크
- dockerfile
- Javascript
- RAPA
- IaaS
- worker
- mysql
- 클라우드
- PAT
- express
- gns3
- kubernetes
- PaaS
- nodejs
- RAID
- docker
- OpenStack
- 개념
Archives
- Today
- Total
목록2020/09/11 (1)
융융이'Blog
단어 변환
counts = [] def solution(begin, target, words): answer = 0 visited = [0] * len(words) print(visited[0] == 0) if target in words: print("있음") find_array(begin, words, visited, 0, target) answer = print(min(counts)) else: return answer # if last_check(words, target): return answer def check(last, target): count = 0 for i in range(len(target)): if last[i] == target[i]: count += 1 if count == len(ta..
2022이전/알고리즘(하루에하나씩!)
2020. 9. 11. 01:25